Question

if alpha and beta are zeroes of x^2-x-6 then find the value of alpha and beta.​

Answer 1

Answer:

x^2-x-6=0

=> x^2-3x+2x-6=0

=> x(x-3)+2(x-3)=0

=> (x-3)(x+2)=0

=> x-3=0

=> x=3

again, x+2=0

x= -2

so, alpha=3 and beta = -2