If alpha and beta are zeroes of x2+5x+5 find value of alpha -1 and beta-1.
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p (x)=X square + 5 x + 5
as alpha + beta = -b/a
and alpha. beta = C/a
then, alpha + beta = -5 ------1
and, alpha beta =5
then,
(alpha-1)+(beta-1) =?
alpha+beta-2=24-2=22
(alpha-1) (beta -1)=(alpha beta ) - (beta+ alpha )+1 = 5+5+1 = 11
and you can find the value of alpha and beta and then subtracting one from each you will get alpha -1 and beta -1
as alpha + beta = -b/a
and alpha. beta = C/a
then, alpha + beta = -5 ------1
and, alpha beta =5
then,
(alpha-1)+(beta-1) =?
alpha+beta-2=24-2=22
(alpha-1) (beta -1)=(alpha beta ) - (beta+ alpha )+1 = 5+5+1 = 11
and you can find the value of alpha and beta and then subtracting one from each you will get alpha -1 and beta -1
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