Question

If alpha and beta are zeroes of x2+5x+8 then find value of (1/alpha+1/beta))

Answer 1

Step-by-step explanation:

$given \\p(x) = x2 + 5x + 8 \\ \alpha + \beta = - b \div a \\ \alpha + \beta = - 5 \\ \alpha \beta = c \div a \\ \alpha \beta = 8$

1/alfa+1/beeta=alfa+beeta/alfa.beeta

=-5/8

mark me as brainliest....

Answer 2

Answer:

-5/8

Step-by-step explanation: