if alpha and beta are zeroes of y^2 + 5y + m , find the value of m such that [α + β]^2 - αβ = 24
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we know here that
m = alpha × beta......
and we ALSo know that alpha + beta = 5......from the given quadratic equation. ..
there fore substituting the values we get ...
(5)^2 - m = 24
therefore..
25 - m = 24
therefore
m = 1 ....
m = alpha × beta......
and we ALSo know that alpha + beta = 5......from the given quadratic equation. ..
there fore substituting the values we get ...
(5)^2 - m = 24
therefore..
25 - m = 24
therefore
m = 1 ....
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