if alpha and beta are zeros of a quadratic polynomial 4 x square + 4 x + 1 then form a quadratic polynomial whose zeros are 2 alpha and 2 Beta
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Answered by
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α and β are the zeroes of 4x² + 4x +1
a = 4
b =4
c = 1
sum of zeroes = -b/a
α + β = -b/a
α+ β = -4 /4
α + β = -1 ........................(i)
product of zeroes = c/a
αβ = c/a
αβ = 1/4 ................(ii)
zeroes of polynomial are 2α and 2β
so
sum of zeroes =
2α + 2 β
2(α+β) from (i)
2(-1)
-2
product of zeroes
(2α)(2β)
4αβ
4 (1/4) from (ii)
1
polynomial =
x ² - ( sum of zeroes )x + product of zeroes
x² - (-2)x +1
x² +2 x+1
a = 4
b =4
c = 1
sum of zeroes = -b/a
α + β = -b/a
α+ β = -4 /4
α + β = -1 ........................(i)
product of zeroes = c/a
αβ = c/a
αβ = 1/4 ................(ii)
zeroes of polynomial are 2α and 2β
so
sum of zeroes =
2α + 2 β
2(α+β) from (i)
2(-1)
-2
product of zeroes
(2α)(2β)
4αβ
4 (1/4) from (ii)
1
polynomial =
x ² - ( sum of zeroes )x + product of zeroes
x² - (-2)x +1
x² +2 x+1
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Thanks
Answered by
227
Answer:
Step-by-step explanation:α and β are the zeroes of 4x² + 4x +1
a = 4
b =4
c = 1
sum of zeroes = -b/a
α + β = -b/a
α+ β = -4 /4
α + β = -1 ........................(i)
product of zeroes = c/a
αβ = c/a
αβ = 1/4 ................(ii)
zeroes of polynomial are 2α and 2β
so
sum of zeroes =
2α + 2 β
2(α+β) from (i)
2(-1)
-2
product of zeroes
(2α)(2β)
4αβ
4 (1/4) from (ii)
1
polynomial =
x ² - ( sum of zeroes )x + product of zeroes
x² - (-2)x +1
x² +2 x+1
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