if alpha and beta are zeros of f(x)=4x²-5x-1 then evaluate(1)=alpha²+beta². (2) alpha³+beta³. (3). alpha⁴+beta⁴ (4) alpha²- beta²
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for the zeroes
a=4
b=-5
c=-1
we know that
alpha +beta= -b/a
=-(-5) /4
=5/4
and, alpha. beta=c/a
=-1/4
for(1) alpha²+beta²=(alpha+beta) ² _ alpha. beta
= (5/4) ² _ 2(-1/4)
= 25/16 - 1/2
=25 -8/16
=17/16
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