Math, asked by sarita22pandey81, 1 month ago

if alpha and beta are zeros of p(x)=3x^2+4x+2the value of (alpha beta^2+beta alpha ^2) is​

Answers

Answered by pranjaligupta2106
0

Answer:

We have,

3x

2

−4x+1=0

α+β=

3

4

α.β=

3

1

β

2

α

2

+

α

2

β

2

=

αβ

(α+β)(α

2

2

−α.β)

=

3

1

(α+β)((α+β)

2

−3αβ)

=4(

9

16

−1)=

9

4×7

=

9

28

β

α

2

×

α

β

2

=αβ=

3

1

Hence,

quadratic equation whose roots are

β

α

2

and

α

β

2

:

⇒x

2

9

28

x+

3

1

=0

9x

2

−28x+3=0

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