if alpha and beta are zeros of p(x)=3x^2+4x+2the value of (alpha beta^2+beta alpha ^2) is
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Answer:
We have,
3x
2
−4x+1=0
α+β=
3
4
α.β=
3
1
β
2
α
2
+
α
2
β
2
=
αβ
(α+β)(α
2
+β
2
−α.β)
=
3
1
(α+β)((α+β)
2
−3αβ)
=4(
9
16
−1)=
9
4×7
=
9
28
β
α
2
×
α
β
2
=αβ=
3
1
Hence,
quadratic equation whose roots are
β
α
2
and
α
β
2
:
⇒x
2
−
9
28
x+
3
1
=0
9x
2
−28x+3=0
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