Question

if alpha and beta are zeros of p(x)=5x²+4x-9 then find the value of alpha⁴-beta⁴

Answer 1

↑ Here is your answer ↓
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Given polynomial

$5x^2 +4x-9 = 0$

Solve it

$5x^2 +9x - 5x - 9 = 0$

$x(5x+9) - 1(5x+9)= 0$

$(x-1)(5x+9)=0$

$\alpha = 1, \beta = -9/5$

Now

$= \alpha^4 - \beta^4$

$=1^4 - (-9/5)^4$

$= 1 + 6561/625$

$= 10.3976$

Answer 2

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