Question

if alpha and beta are zeros of polynomial 3 x²- 12 x + K, Alpha minus beta= 2 find k​

Answer 1

Answer:

$3 {x}^{2} - 12x + k \\ sum \: of \: zeroes = \frac{ - b}{a} \\ \alpha + \beta = \frac{12}{3} = 4 \\ \alpha - \beta = 2 \\ adding \: these \: two \:. 2 \alpha = 6 \\ \alpha = 3 \\ \beta = 1 \\ product \: of \: zeroes = \frac{c}{a} \\ \alpha \beta = \frac{k}{3} \\( 3) (1) = \frac{k}{3} \\ k = 9$