Math, asked by onkarsalunkhe1oyd8x4, 1 year ago

if alpha and beta are zeros of polynomial 4x 2 -2x+(k-4) and α=1/β find k

Answers

Answered by Ashish02
212
alpha × beta = c / a = (k-4)/4

given that

alpha=1/beta

alpha×beta = 1

(k-4)/4 = 1

k-4 = 4

so k = 8
Answered by VaibhavSR
8

Answer: k=8

Step-by-step explanation:

  • Given Quadratic equation is 4x^{2} -2x+(k-4)=0 where a=4, b=-2 and c=(k-4).
  • We know product of roots \alpha \beta =\frac{c}{a}
  • Given, \alpha =\frac{1}{\beta }

                  ∴ \alpha \beta =1

  • Now according to question,

        \frac{c}{a}=1

    ⇒\frac{k-4}{4}=1

    ⇒k-4=4

    ⇒k=4+4

   ∴ k=8

  • Hence,the value of k is 8 in the above quadratic equation.

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