if alpha and beta are zeros of polynomial 6 xsquare - 7 x minus 3 form quadratic polynomial whose zeros are 2 alpha and 2 beta
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The polynomial can be factored into: (x+1)(2x-5), so we have α = -1 and β = 5/2
(i) The polynomial with zeros α2 and β2 can be factored as (x - α2)(x - β2). This can be multiplied out to get
x2 - (α2 + β2)x + α2β2 or x2 - (1 + 25/4)x + 25/4 or x2 - (29/4)x + 25/4
Multiply all the terms by 4 to get 4x2 - 29x + 25
See if you can now do part (ii)
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