Question

if alpha and beta are zeros of polynomial 6x square - 7 x minus 3 then form a quadratic polynomial whose zeros are 1 upon alpha and one upon beta

Answer 1

$hi \: mate \\ \\ \alpha + \beta = 7 \div 6 \\ \\ \alpha \beta = - 3 \div 6 = - 1 \div 2 \\ \\ required \: quadratic \: equation \: in \: x \: is \: \\ \\ x {}^{2} - (1 \div \alpha + 1 \div \beta )x + ( 1 \div \alpha \beta ) \\ \\ = > 1 \div \alpha \: \: + 1 \div \beta \: \: \: = \alpha + \beta \div \alpha \beta = - 7 \div 3 \\ \\ \\ 1 \div \alpha \times 1 \div \beta = - 2\\ \\ \\ x {}^{2} - ( - 7 \div 3)x + ( - 2) \\ \\ have \: a \: great \: day$

Answer 2

Okkkkkkkkkk(kkkkkkkkkkkkk