Question

if alpha and beta are zeros of polynomial 6x square + X - 2 find the value of alpha and beta beta upon Alpha
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Answer 1

Answer:

alfa = -1\6& beta = -1\3

let coefficient of x^2 be a coefficient of x be b and -2 be c

We know alfa × beta = -b\a and alfa \ beta = c\a

therefore alfa beta = -1\6 and alfa divided by beta = -1\3

Answer 2

$\huge \tt \it \bf \it \bm { \mathbb{ \fcolorbox{blue}{yellow}{ \red{ANSWER :}}}} \green\longrightarrow$

$\large \red{equation} = >$

$6 {x}^{2} + x - 2 \\ = > 6 {x}^{2} + 4x - 3x - 2 \\ = > 2x(3x + 2) - 1(3x + ) \\ = > (2x - 1)(3x + 2)$

$x = \frac{1}{2} and \: x = \frac{2}{3}$

so,

$\boxed{ \alpha = \frac{1}{2}} \\ \\ \boxed{\beta = \frac{2}{3} }$

ɳѳw

${ \green{ \frac{ \beta }{ \alpha } = \frac{ \frac{ \frac{2}{3} }{1} }{2} }} \\ \green{ = > \frac{2}{3} \times \frac{2}{1} } \\ \\ = > {\boxed{ \large { \red{ \frac{ \beta }{ \alpha} = \frac{4}{3} }}}}$