if alpha and beta are zeros of polynomial F(X) = x square - 5 + 3 and Alpha minus beta =1,than find k
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hey dear user!!!!
your answer ⤵⤵
α+β= 5
αβ=k
α - β =1
(α - β)2 = 1
(α + β)2 - 4αβ = 1
52 - 4k = 1
25-4k=1
4k=24
k=6
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✖✖✖✖or ✖✖✖✖
x2-5x+k
Here, a=1, b=-5 and c=k
Now, alpha+beta= -b/a= -(-5)/1= 5
alpha*beta= c/a= k/1= k
Now, apha-beta=1
Squaring both sides, we get,
(alpha-beta)2=12
=> (alpha+beta)2-4*aplha*beta=1
=> (5)2-4k=1
=> -4k= 1-25
=> -4k= -24
=> k=6
So the value of k is 6.
Hope it helps!!
Cheers!
〰〰〰〰〰〰〰〰〰〰〰
your answer ⤵⤵
α+β= 5
αβ=k
α - β =1
(α - β)2 = 1
(α + β)2 - 4αβ = 1
52 - 4k = 1
25-4k=1
4k=24
k=6
〰〰〰〰〰〰〰〰〰〰〰〰〰
✖✖✖✖or ✖✖✖✖
x2-5x+k
Here, a=1, b=-5 and c=k
Now, alpha+beta= -b/a= -(-5)/1= 5
alpha*beta= c/a= k/1= k
Now, apha-beta=1
Squaring both sides, we get,
(alpha-beta)2=12
=> (alpha+beta)2-4*aplha*beta=1
=> (5)2-4k=1
=> -4k= 1-25
=> -4k= -24
=> k=6
So the value of k is 6.
Hope it helps!!
Cheers!
〰〰〰〰〰〰〰〰〰〰〰
krrish53:
galat hai
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