Question

if alpha and beta are zeros of polynomial x^2-3x+2 then find alpha^2(beta)+alpha (beta)^2​

Answer 1

Answer:

α²*β +α*β² = 6

Step-by-step explanation:

Sum of zeroes = 3/1   ⇒ α + β = 3

Product of zeroes = 2/1 ⇒ α*β = 2

Now, α²*β +α*β² = α*β(α+β) = 3*2 = 6