Question

if alpha and beta are zeros of polynomial x square minus 4 root 3 X + 3 then find the value of alpha + beta minus alpha beta​

Answer 1

Answer:

Step-by-step explanation:

f{x}=$x^{2}$ + $\sqrt[4]{3}$x +3

zeros = alpha ,beta

alpha + beta - {alpha*beta} = {to be calculated}

a=1

b=$\sqrt[4]{3\\}$

c=3

sum of zeros{$\alpha +\beta$}=   -b/a

= -{$\sqrt[4]{3}$} / 1

=  -$\sqrt[4]{3}$

product  of zeros=c/a

$\alpha \beta$= 3/1

= 3

$\alpha +\beta - \alpha \beta$=  -$\sqrt[4]{3}$ -3

=  -1 {$\sqrt[4]{3}$+3}

HOPE THIS HELPS

MARK ME AS BRAINLIEST