Question

if alpha and beta are zeros of polynomial x²-4x+9 find a quadratic polynomial whose zeros are 3 alpha and 3 beta

Answer 1

The Discriminant of the given eqⁿ is;

D = b² - 4ac

D = (-4)² - 4 × 1 × 9

D = 16 - 36

D = -20

And the quadratic eqⁿ whose D < 0 has no real roots.

So this question has some mistakes please recheck it.

Answer 2

Answer:

Hope it helps you

Step-by-step explanation:

alpha and beta are the zeros of x^2-4x+9

alpha+beta=-b/a=4

alpha×beta=c/a=9

now equation (zeroes are 3 alpha and 3 beta)

x^2+(-(3alpha + 3 beta)x) + (3 alpha × 3 beta)

=x^2 -3(alpha + beta)x + (9(alpha × beta))

=x^2-3(4)x + 9(9)

=x^2 - 12x + 81

Hence proved