Question

If alpha and beta are zeros of polynomial x2 -7x+10,then form a quadratic polynomial whoes zeros are half the zeros of the given polynomial

Answer 1

${x}^{2} - 7x + 10$

${x}^{2} - 2x - 5x + 10 \\ x( x - 2) - 5(x - 2) \\( x - 5)(x - 2) = 0 \\ x = 2 \\ x = 5$

${x}^{2} - (1 + 5 \div 2)x + 10 \div 4 \\ {x}^{2} - 7x \div 2 + 5 \div 2$