if alpha and beta are zeros of quadratic polynomial f(x)= kx^2+4x-4, such that alpha^2+beta^2=24 find k
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Answer:
Step-by-step explanation:
Sum of roots of a quadratic equation= -coefficient of x÷coefficient of x²
Product of roots of the quadratic equation= constant÷coefficient of x²
sum of roots= alpha +beta= -4÷k
product of roots=-4÷k
alpha² + beta²= (alpha+beta)²- 2×alpha×beta
Given: alpha²+ beta²=24;
24= (16÷k²)+(8÷k)
24k²=16+8k
3k²=2+k
3k²-k-2=0
3k²-3k+2k-2=0
3k(k-1)+2(k-1)=0
k=1 or k=-2÷3
Thus k can take two values as mentioned above.
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