Question

If alpha and beta are zeros of quadratic polynomial f(x)=x^2-p (x+1)-csuch that (alpha+1)(beta+1)=0then c is equal to

Answer 1

Answer:

c = p/2

Step-by-step explanation:

the quadratic equation is x^2 - px - p - c

now alpha + beta = p

alpha * beta = -p

(alpha + 1)(beta + 1) = 0

alpha + beta + 2 (alpha * beta) = 0

p + ( -2p - 2c ) = 0

-p - 2c = 0

2c = p

c = p/2

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Answer 2

Hope it helps ! mark as brainliest