if alpha and beta are zeros of quadratic polynomial X square + 2 X + 1 find the value of one by Alpha Plus One by beta
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Answered by
77
Proper Question : If α and ß are Zeroes of Quadratic Polynomial x² + 2x +1 . Find the Value of 1/α + 1/ß
Solution :
In this Question, It is Given that α and ß are Zeroes of Quadratic Polynomial x² + 2x +1 .
Quadratic Polynomial = x² + 2x + 1
Here, a= 1 , b = 2 and C = 1
•°• Sum of Zeroes = -b/a ✒ -(Coefficient of x)/Coefficient of x²
°•° Sum of Zeroes = -(2)/1 ✒ -2
Also, Product of Zeroes = c/a ✒ Constant term Coefficient of x²
•°• Product of Zeroes = 1/1 ✒ 1
Now, From the Quadratic Polynomial!
Let the Polynomial be f(x)
•°• f(x) = x² + 2x + 1
Sum of Zeroes of Polynomial and Product of Zeroes of Polynomial are (-2) and (1) Respectively!
✏ Value of 1/α + 1/ß
✏ α+ß/ab
✏ -2 / 1
✏ -2
[ Therefore, Required Value of the 1/α + 1/ß is (-2) ]
Solution :
In this Question, It is Given that α and ß are Zeroes of Quadratic Polynomial x² + 2x +1 .
Quadratic Polynomial = x² + 2x + 1
Here, a= 1 , b = 2 and C = 1
•°• Sum of Zeroes = -b/a ✒ -(Coefficient of x)/Coefficient of x²
°•° Sum of Zeroes = -(2)/1 ✒ -2
Also, Product of Zeroes = c/a ✒ Constant term Coefficient of x²
•°• Product of Zeroes = 1/1 ✒ 1
Now, From the Quadratic Polynomial!
Let the Polynomial be f(x)
•°• f(x) = x² + 2x + 1
Sum of Zeroes of Polynomial and Product of Zeroes of Polynomial are (-2) and (1) Respectively!
✏ Value of 1/α + 1/ß
✏ α+ß/ab
✏ -2 / 1
✏ -2
[ Therefore, Required Value of the 1/α + 1/ß is (-2) ]
smartyAnushka:
Nice answer dear..... :)
Answered by
54
Given that : α and β are Zeroes of Quadratic Polynomial x² + 2x +1 .
Let the Quadratic Polynomial be f(x)
f(x)= x² + 2x +1 .
Sum of Zeroes = -b/a => -(Coefficient of x)/Coefficient of x²
Sum of Zeroes = -(2)/1 -2
Product of Zeroes = c/a => Constant term Coefficient of x²
Product of Zeroes = 1/1
= Value of 1/α + 1/ β
= α+. β/aβ
= -2 /1
= -2
Hence, Required Value of the 1/α + 1/ß is (-2)
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