Question

if alpha and beta are zeros of the polynomial x^2+7x+3, find a quadratic polynomial whose zeroes are alpha/beta and beta/alpha​

Answer 1

Answer:

Given that,

α,β  are the zeroes of the polynomial  p(x)=2x2−7x+3

Sum of zeroes (α+β)=a−b=2−(−7)=27

Product of zeroes αβ=ac=23

∴α2+β2=(α+β)2−2αβ

                =(27)2−2(23)

  

=449−41

 

 =437

Answer 2

Answer:

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