if alpha and beta are zeros of the polynomial x square - 3K X + K square find K square if Alpha square + beta square = 28
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x²-kx+k²
solution
α²+β²=(α+β)²-2αβ→(1)
given
α²+β²=28
and we know α+β = -b/a
αβ = c/a
substuting in eq (1)
we get
28 =(-3k)²-2k²
28 =9k²-2k²
7k² =28
k² =4
k=±2
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