If alpha and beta are zeros of the polynomial x square - 6 X + a find a is beta is -2
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Answer:
a=-16
Step-by-step explanation:
If p and q are the zeros of of a quadratic equation ax^2+bx+c=0 then
p+q=(-b/a) and p*q=c/a
utilizing this we have
polynomial p(x)=1*x^2+(-6)*x+a=0
p+q=-(-6)/1=6
p*q=a/1
But given q=-2
so,p=(6-q)=6-(-2)=8
a=p*q=8*(-2)=-16
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