Question

If alpha and beta are zeros of x2-x-6 then find the value of alpha -beta

Answer 1

Given equation is

${x}^{2} - x - 6 = 0$

If we factorize, we get

${x}^{2} + 2x - 3x - 6 = 0$

Taking common we get

$x(x + 2) - 3(x + 2) = 0$

so, we get

$(x + 2)(x - 3) = 0$

Separating the terms , we get

$x + 2 = 0 \: \: or \: x - 3 = 0$

so the final answers are

$x = - 2 \: \: or \: \: 3$

let

$\alpha = - 2 \: and beta = 3 \\ we \: get \: \\ - 2 - 3 = - 5$

If

$\alpha = 3 \: and \: beta = - 2 \\ we \: get \\ 3 - ( - 2) = 5$

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