Question

if alpha and beta are zeros of y2+5y +m , find (alpha +beta)2 - alpha beta =24

Answer 1

if this question is about m here is your answer

Answer 2

Given [tex]p(y)= y^2+5y+m [/tex]
Let $\alpha , \beta$ be the zeroes of $p(y)$
Also, $(\alpha +\beta) -\alpha\beta = 24$

We know, Sum of zeroes = $\frac{-b}{a}$
$\implies \alpha + \beta = 5$
And product of zeroes = $\frac{c}{a}$
$\implies \alpha \beta = m$
substituting values of $(\alpha + \beta) & (\alpha \beta)$
$\implies (-5)^2 - m = 24$
$\implies 25-m=24$
$\implies m=1$