If alpha and beta arevthe zeroes of the polynomial x square minus P(x+1)+ c such tha alpha plus 1 and beta plus 1 is zero
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Answer:
C=2
Explanation:
x²-P(x+1)+c
x²-Px+P+c
So,α+β=-b÷a=P ----------equation 1
α+1+β+1=0
α+β+2=0
by equation 1
P+2=0
P=-2
Zero of polynomial is x=-2
x²-Px+P+c
(-2)²-(-2×{-2})+(-2)+c=0
-4+4-2+c=0
c=2
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