if alpha and beta be the zeroes of the polynomial 2x^2+3x-6 then find the value of alpha^2 beta+alpha beta^2
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Answer:
2x²+3x-6=0
a=2, b=3 ,c=-6
alpa + beta = -3/2
alpa(beta)=-3
(alpa)²+(beta)²= (alpa+beta)²- 2(alpa) beta
= (-3/2)² - 2(-3)
= 9/4 + 6
= 9 + 24/4
= 33/4
I hope it will help you!
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