Question

If alpha and beta be the zeroes of the quadratic polynomial 2-3x -x^2 then find the value of alpha +beta (1+alpha )

Answer 1

Answer:

- 5

Step-by-step explanation:

For quadratic equation x² + 3x - 2 = 0

α + β = - b / a = -3 / 1 = - 3

α*β = c / a = -2 / 1 = - 2

Now, α + β(1+α) = α + β + α*β = -3 + (-2) = -5

Answer 2

Answer:

-5

Step-by-step explanation: