Question

if alpha and beta of a polynomial X square + 6 X + 9 the form of polynomial whose zeros are minus Alpha minus beta​

Answer 1

α + β (Sum of the zeroes) = -(Coefficient of x)/Coefficient of x^2

=> α + β = -6

αβ (Product of the zeroes) = Constant/Coefficient of x^2

=> αβ = 9

Since

α=-α

β=-β

α + β = -α -β = -(α + β) = 6

αβ = -α x -β = -(αβ) = -9

General form of a quadratic polynomial

x^2 - (α + β)x + (αβ)

=> x^2 - (6)x + (-9)

=> x^2 - 6x - 9