if alpha and beta the product of two zeros of the polynomial p(x) 3x2-10x+7 find the value of alpha2 and beta2
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In the given equation
The coefficenents of A,B,C are
3,-10,7 respectively
As we know that product of root =
Alpha x Beta = C/A
Alpha x Beta = 7/3..............(i)eq
and also we know that sum of roots =
Alpha + Beta = -B/A
Alpha + Beta =10/3
Alpha = 10/3 - Beta..............(ii)eq
Put Alpha in eq (i)
(10/3 - Beta ) x Beta = 7/3
10/3 Beta - Beta^2 = 7/3
Beta^2 - 10/3 Beta + 7/3 = 0
(multiply the equation by 3)
3 Beta^2 - 10 Beta +7=0
on solving the equation we get Beta=1
or
Beta=7/3
.....................
Now put Beta in equation (ii)
Alpha = 10/3 -1
Alpha= 7/3
or
Alpha=10/3-7/3
Alpha=1
The coefficenents of A,B,C are
3,-10,7 respectively
As we know that product of root =
Alpha x Beta = C/A
Alpha x Beta = 7/3..............(i)eq
and also we know that sum of roots =
Alpha + Beta = -B/A
Alpha + Beta =10/3
Alpha = 10/3 - Beta..............(ii)eq
Put Alpha in eq (i)
(10/3 - Beta ) x Beta = 7/3
10/3 Beta - Beta^2 = 7/3
Beta^2 - 10/3 Beta + 7/3 = 0
(multiply the equation by 3)
3 Beta^2 - 10 Beta +7=0
on solving the equation we get Beta=1
or
Beta=7/3
.....................
Now put Beta in equation (ii)
Alpha = 10/3 -1
Alpha= 7/3
or
Alpha=10/3-7/3
Alpha=1
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