Question

if alpha and beta zeros of polynomial 6 y square - 7y+2 to find a quadratic polynomial whose zeros are one by Alpha and one by beta

Answer 1

6ysq.-7y+2=0
$6 {y}^{2} - 4y - 3y + 2 = 0 \\ 2y(3y - 2) - 1(3y - 2) = 0 \\ (3y - 2)(2y - 1) = 0 \\ y = 2 \div 3 \\ y = 0.6666.. \\ also \: y = 1 \div 2 = 0.5 \\ so \: here \: \alpha = 0.6666.. \\ second \: eqution \: be \\ x = 1 \div \alpha \\ 1 \div 0.66... = 3 \div 2 = 1.5 \\ y \: being \: second \: root \: be \: 1 \div \beta = 1 \div 0.5 = 2 \\ \\ {x}^{2} - sum \: of \: roots + products \: of \: roots \\ {x}^{2} - 3.5x + 3$

Answer 2

Answer:

Step-by-step explanation: