Question

If alpha and bheta are the zeroes of p(x) = x^2 + x - 1 then find 1/alpha + 1/bheta.

Answer 1

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Hi there !!

Hi there !!

p(x) = x² + x - 1

a = 1

b = 1

c = -1

α and β are zeros of p(x)

α + β =  -1                [α + β = -b/a ]

αβ = -1                    [αβ = c/a ]

To find :-

1/α + 1/β

1/α + 1/β =  α + β / αβ

               = -1/-1

               = 1

1/α + 1/β = 1