Question

if alpha and bita are the roots of the quadratic equation ax²+bx+c=0 then 1/alpha+b + 1/abita+b=​

Answer 1

Step-by-step explanation:

if alpha is root

a(alpha)²+b(alpha) = -c

a(beta)²+b(beta)= -c

[1/a(alpha)+b]×(alpha)/(alpha)=(alpha)/-c

same for beta then (beta)/-c

1/a(alpha)+b +1/a(beta)+b =b/AC

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