Question

If alpha and bita are the roots of the quadratic polynomial f(x)=ax square +bx +c, then find the value of alpha-bita

Answer 1

Answer:

ax2+bx+c=0

ax2+bx+c=0α+β=−abαβ=ac

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2(α−β)2=(α+β)2−4αβ

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2(α−β)2=(α+β)2−4αβ=a2b2−a4c=a2b2−4ac

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2(α−β)2=(α+β)2−4αβ=a2b2−a4c=a2b2−4acα−β=ab2−4ac

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2(α−β)2=(α+β)2−4αβ=a2b2−a4c=a2b2−4acα−β=ab2−4acα2−β2=(α+β)(α−β)=a−b(ab2−4ac)

ax2+bx+c=0α+β=−abαβ=ac(α+β)2=a2b2(α−β)2=(α+β)2−4αβ=a2b2−a4c=a2b2−4acα−β=ab2−4acα2−β2=(α+β)(α−β)=a−b(ab2−4ac)=

Explanation:

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