Question

if alpha and bita are the zeroes of p(x)=x square-x-4then find the value of alpha upon bita plus bita upon alpha

Answer 1

Hola there,

p(x) = x² - x - 4

a = 1
b = -1
c = -4

So,

α + β = -b/a = 1
&
αβ = c/a = -4

Now,

=> α/β + β/α

=> (α² + β²)/αβ

=>[(α + β)² - 2αβ]/αβ

=> (1² - 2(-4))/(-4)

=> (1 + 8)/(-4)

=> -9/4. ...Ans

Hope this helps...:)