if alpha and bita are the zeroes of polynomial 2x*x-3x+k than find the values of k such that alpha's spuare +bita's spuare =50
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Here is
Solution:
α and β are zeroes of polynomial
2x^2 -3x + k
THEN
α+β = -b/a => 3/2 , αβ = c/a => k/2
⇒ (α+β)² = (3/2)²
⇒ α²+ β²+ 2αβ = 9/4
⇒ 50 + 2k/2=9/4
⇒ k = 9/4 - 50
K => (9-200)/4
K=> -191/4 Ans
Here is
Solution:
α and β are zeroes of polynomial
2x^2 -3x + k
THEN
α+β = -b/a => 3/2 , αβ = c/a => k/2
⇒ (α+β)² = (3/2)²
⇒ α²+ β²+ 2αβ = 9/4
⇒ 50 + 2k/2=9/4
⇒ k = 9/4 - 50
K => (9-200)/4
K=> -191/4 Ans
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