If alpha and bita are the zeroes of the polynonial f(x)=5x^2-7X+1 then find the value of {alpha/bita+bita /alpha
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Step-by-step explanation:
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Answer:
5
Step-by-step explanation:
= alpha+bita= -b/a, alpha*bita=c/a
= -b/a=7/5, c/a=1/5
= (alpha/bita)+(bita/alpha)=(alpha^2+bita^2)/alpha*bita
ie .((7/5)^2-2/5)/1/5
= (49/35-2/5)/1/5
= (35/35)*5/1
= 5
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