Question

If alpha and bita are the zeroes of the quadratic polynomial x^2-4x-12 then the value of ą^3b and ąb^3

Answer 1

Answer:

hii I think that the answer is correct

${x}^{2} - 4x - 12$

${x}^{2} - 6x + 2x - 12$

$x(x - 6) + 2(x - 6)$

$(x + 2)(x - 6) = 0$

$x = - 2 \\ x = 6$

hence, alpha is -2 and bits is 6