If alpha and bita are the zeroes of the quadratic polynomial x2+x-2.then find a polynomial whose zeroes are 2alpha+1 and 2 bita +1
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Two Methods:
If α & β are zeroes of f(x) =x²-x-2
then
α + β = -b/a = 1
α β = c/a = -2
let α’ =2α+1 & β’ = 2β+1
α’ + β’ = 2α+1 + 2β+1
=2α+2β+2 =2(α+β)+2 =2(1)+2=4
α’ β’=(2α+1)(2β+1) = 4α β+2α+ 2β+1 = 4(-2)+2(1)+1=-8+2+1=-5
Polynomial having α’ & β’ as zeroes is given by
k (x²-(α’ + β’)x +α’ β’)
= k (x² - 4x -5) Answer
By giving different values to k, there can be infinite polynomials
Second method:
f(x) =x²-x-2 =x² -2x + x -2 = x(x-2) +1(x-2) =(x+1)(x-2)
so two zeroes are -1 and 2
α = -1 & β= 2
α’ = 2α + 1 = 2(-1)+1 = -1
β’ = 2β +1= 2(2)+1=5
Polynomial having α’ & β’ as zeroes is given by
k (x²-(α’ + β’)x +α’ β’)
k (x²-(-1 + 5)x +(-1)(5))
= k (x² - 4x -5) Answer
By giving different values to k, there can be infinite polynomials
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