if alpha and bita are the zeros of p(x) =x square-5x+sygma such that alpha - bita =1,then find sygma h
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sum of zeroes=-b/a=-(-5)/1=5
product 0f zeroes=c/a=y/1
then,
a+b=5
a -b=1
by solving the equation (I) and (ii), by elimination method,
a+b=5
a -b=1
_+___-__
2b=4
b=4/2=2
again,,
put the value of b in (I) equation
a+b=5
a+2=5
a=5-2
a=3
A/Q
substitute the value of an
=) ab=y/1
=)3*2=y/ 1
=)6=y/1
=)y=6
sum of zeroes=-b/a=-(-5)/1=5
product 0f zeroes=c/a=y/1
then,
a+b=5
a -b=1
by solving the equation (I) and (ii), by elimination method,
a+b=5
a -b=1
_+___-__
2b=4
b=4/2=2
again,,
put the value of b in (I) equation
a+b=5
a+2=5
a=5-2
a=3
A/Q
substitute the value of an
=) ab=y/1
=)3*2=y/ 1
=)6=y/1
=)y=6
sanaya52:
ok
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