If alpha and Bita are zeroes of polynomial 3x2+2x-6 then find the value of alpha cube + Bita cube
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Step-by-step explanation:
Given polynomial = 3x2+2x−6x=3x2−4x=x(3x−4)—(1)
The zeroes are α and β
(1)=>α=0,β=43
OR α=43,β=0
Rest can be computed.
Some of the terms involve 1α or 1β , which will result in dividing by zero !
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