if alpha and bita are zeroes of polynomial x2-4x+3 find the value of alpha and bita cube
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Answer:
x^2-4x+3
x^2-3x-x+3
x(x-3)-1(x-3)
(x-3)(x-1)
x-3=0
x=3
& x-1=0
x=1.
alpha is 3 & bita is 1
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