If alpha and bita are zeroes of the polynomial x^2-5 then form a quadratic polynomial whose zeroes are1+alpha and 1+bita
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Answer:
-6
Step-by-step explanation:
αβ=c/a=-5
α+β=-2
now,α=1+α
β=1+β
=(αβ+αβ×β+α×αβ+αβ)/αβ
substitute above values
=20+((-5)(-2))/-5
=20+10/-5
=-30/5
=-6
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Answer:
Step-by-step explanation: please mark as brainest
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