if alpha and bitta are zeroes of x^2-4root3x+3. find alpha+bitta-alpha×bitta
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udaywatts41:
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HEY MATE...
WE KNOW THAT...
SUM OF ZEROES= –b/a
Product of the ZEROES= c/a
So the equation is as => x²–4√3x+3_____[1]
==>> And the Quadratic equation is as = ax²+bx-c=0__________[2]
So Comparing both equation [1] and [2]
We get
a= 1
b= 4√3
c= 3
So now.,
We have to find
alpha+Bitta= alpha×bitta...
...
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