Question

If alpha and bitta are zeroes of x2-5x+k and alpha-bitta=1 find k​

Answer 1

hope it helps...

thanks

Answer 2

ANSWER:

• Value of k is 6.

GIVEN:

• α and β are zeros of x²-5x+k .
• α-β = 1

TO FIND:

• Value of'k'.

SOLUTION:

Formula:

=> (α+β)² = (α-β)²+4αβ. .....(I)

=> Sum of zeros (α+β) = -(Coefficient of x)/Coefficient of x²

=> Product of zeros (αβ) = Constant term/ Coefficient of x²

P(x) = x²-5x+k

Sum of zeros (α+β) = -(-5)/1

=> (α+β) = 5

=> (α-β) = 1. (Given)

Product of zeros (αβ) = k/1

=> αβ = k

Putting these values in the formula we get;

=> (5)² = (1)²+4k

=> 25 = 1 +4k

=> 25-1 = 4k

=> 24/4 = k

=> 6 = k

Value of k is 6.

NOTE:

Some important formulas

(a+b)² = (a-b)²+4ab

(a-b)² = (a+b)²-4ab