if alpha and one by Alpha as zeros of the polynomial 4 x ^ 2 - 2 X + K - 4 find the value of k
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Let the given polynomial be p(x) = 4x2 − 2x +(k − 4) Given α and 1/α are zeros of the given polynomial Product of zeroes = (c/a) That is ( α ×1/α) = (k − 4)/4 ⇒ 1 = (k − 4)/4 ⇒ 4 = (k − 4) ∴ k = 8
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Let the given polynomial be p(x) = 4x2 − 2x +(k − 4) Given α and 1/α are zeros of the given polynomial Product of zeroes = (c/a) That is ( α ×1/α) = (k − 4)/4 ⇒ 1 = (k − 4)/4 ⇒ 4 = (k − 4) ∴ k = 8
I Hope It Will Help!
^_^
Answered by
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Solution- ----------
Let, alpha denotes by the symbol "£"
Now, According to the question --
product of Zeroes = constant term / coefficient
of x^2.
£ × 1/ £ = (k-4) / 4
1 = (k-4)/4
k-4 = 4
k = 4+4
k = 8........... is the required answer.
↪ Hope this will help you ↩
Let, alpha denotes by the symbol "£"
Now, According to the question --
product of Zeroes = constant term / coefficient
of x^2.
£ × 1/ £ = (k-4) / 4
1 = (k-4)/4
k-4 = 4
k = 4+4
k = 8........... is the required answer.
↪ Hope this will help you ↩
MrThakur14Dec2002:
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