If alpha andbeta are the zeroes of the quadriatic polynomial 5x square minus6xplus1, find a quatratic polynomial whose zeroes are alpha bybeta square and beta by alpha two
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if α and β are 2 zeroes then
α+β=-b/a
=6/5
⇒α=6-5β/5 (i)
α.β=c/a
(6-5β/5)β=1/5
⇒6β-5β²=1
5β²-5β-β+1=0
5β(β-1)-1(β-1)
⇒β=1or1/5
⇒α=1or1/5
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α+β=-b/a
=6/5
⇒α=6-5β/5 (i)
α.β=c/a
(6-5β/5)β=1/5
⇒6β-5β²=1
5β²-5β-β+1=0
5β(β-1)-1(β-1)
⇒β=1or1/5
⇒α=1or1/5
plz mark as brainliest
zubiyamoin3:
thank you
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