if alpha, ß are the roots of x²-x+1=0 then 1/alpha² + 1/beta²=?
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hope the given answer helps you
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Step-by-step explanation:
α+β= _b/a=-(-1)/1=1
αβ=c/a=1/1=1
1/α²+1/β²=β²+α²/α²β²⇒α²+β²/(αβ)²
⇒α²+β²/(αβ)²=(α+β)²-2αβ/(αβ)² [by formula α²+β²=(α+β)²-2αβ]
⇒α²+β²/(αβ)²=1²-2(1)/1²=1-2/1=-1
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