Question

if alpha,beeta are the roots of 4x square +3x+7 equal to zero then I/alpha+1/beeta​

Answer 1

Answer:

4x²+3x+7=0

1/alpha+1/beta

alpha+beta/(alpha×beta)

alpha + beta=-b/a=-3/4

alpha×beta=c/a=7/4 (put value)

(-3/4)/(7/4)

= -3/7

Step-by-step explanation:

HOPE THIS HELP YOU

Answer 2

Answer:

$\frac{ - 3}{7}$

Step-by-step explanation:

$4 {x}^{2} + 3x + 7 \\ \\ \alpha + \beta = \frac{ - b}{a} = \frac{ - 3}{4} \: \: and \\ \alpha \beta = \frac{c}{a} = \frac{7}{4} \\ now \: \\ \frac{ 1}{ \alpha } + \frac{1}{ \beta } = \frac{ \beta + \alpha }{ \alpha \beta } \\ = \frac{ \frac{ - 3}{4} }{ \frac{7}{4} } = \frac{ - 3}{7}$